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Title: Two balls are thrown off a roof of a 25 m building. One is dropped from rest and then later the second is throw outwards with a velocity 10 m/s horizontal and downward component of 15 m/s
Two balls are thrown off a roof of a 25 m building. One is dropped from rest and then later the second is throw outwards with a velocity 10 m/s horizontal and downward component of 15 m/s
Which ball hits the ground first?
With what velocity dud each ball hit the ground?
Which ball travels the greater displacement
Answer:
s = ut + ½at²
ist ball: 25 = 0t + ½9.81t² = displacement
=> t = √[25/4.905] ~= 2.26 s
v = u + at = 9.81 x 2.26 = 22.15 m/s
iind ball:
vertically applying, s = ut + ½at²
=> 25 = 15t + 4.905t²
or t² + 3.058t - 5.097 = 0
solving => t ~= 1.2 s
v = 15 + 9.81(1.2) = 26.772 m/s
horizontal distance travelled ~= 1.2 x 10 = 12 m
therefore resultant displacement = √[(12)² + (25)² ] = 27.73 m (from projecion point)
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